- #include <stdio.h>
- static void print()
- {
- int i, *j = (int *)(&i + 4);
- for (i = 0; i < 6; i++)
- printf("%d%c", *(int *)(j + i + 8), i == 5 ? '\\n' : ' ');
- }
- int main(int argc, char *argv[])
- {
- int array[6] = {1, 1, 2, 3, 5, 8};
- print();
- return 0;
- }
- //该片段来自于http://www.codesnippet.cn/detail/1404201512254.html
来源: http://www.codesnippet.cn/detail/1404201512254.html