写了两个函数.
- int even( int n )
- {
- int ret = 1;
- if (n < 0)
- {
- n = -n;
- }
- if (n % 2 == 1)
- {
- ret = 0;
- }
- return ret;
- }
- int OddSum( int List[], int N )
- {
- int sum = 0;
- for (int i = 0; i < N; i++)
- {
- if (even(List[i]) == 0)
- {
- sum = sum + List[i];
- }
- }
- return sum;
- }
来源: http://www.bubuko.com/infodetail-3313217.html