编写一个名为 printTable() 的函数, 它接受字符串的列表的列表, 将它显示在组织良好的表格中, 每列右对齐. 假定所有内层列表都包含同样数目的字符串. 例如, 该值可能看起来像这样:
- table_data = [['apples', 'oranges', 'cherries', 'banana'],
- ['Alice', 'Bob', 'Carol', 'David'],
- ['dogs', 'cats', 'moose', 'goose']]
你的 printTable() 函数将打印出:
- apples Alice dogs
- oranges Bob cats
- cherries Carol moose
- banana David goose
示例代码 1:
- import copy
- def count_width(the_list):
- new_list = copy.deepcopy(the_list)
- col_widths = [0]*len(the_list)
- i = 0
- while i <len(new_list):
- new_list[i].sort(key=lambda x: len(x), reverse=True)
- col_widths[i] = new_list[i][0]
- i = i+1
- return col_widths
- def list_ljust(the_list):
- widths = count_width(the_list)
- for j in range(len(the_list[0])):
- for i in range(len(the_list)):
- print(the_list[i][j].ljust(len(widths[i])), end=' ')
- print('\r')
- table_data = [['apples', 'oranges', 'cherries', 'banana'],
- ['Alice', 'Bob', 'Carol', 'David'],
- ['dogs', 'cats', 'moose', 'goose']]
- list_ljust(table_data)
sort 方法:
lambda 函数:
示例代码 2:
- def count_widths(the_list):
- col_widths = [0]*len(the_list)
- for i in range(len(the_list)):
- for j in range(len(the_list[0])):
- if len(the_list[i][j])> max_len:
- max_len = len(the_list[i][j])
- col_widths[i] = max_len
- return col_widths
- def list_ljust(the_list):
- widths = count_widths(the_list)
- print(widths)
- for j in range(len(the_list[0])):
- for i in range(len(the_list)):
- print(the_list[i][j].ljust(widths[i]), end=' ')
- print('\r')
- table_data = [['apples', 'oranges', 'cherries', 'banana'],
- ['Alice', 'Bob', 'Carol', 'David'],
- ['dogs', 'cats', 'moose', 'goose']]
- list_ljust(table_data)
来源: http://www.bubuko.com/infodetail-3235934.html