int main(void) { int found, i, k, n; int a[10][10];
- int main()
- {
- int i,j,k,h,n;
- int a[6][6];
- scanf("%d",&n);
- for(i=0;i<n;i++)
- for(j=0;j<n;j++)
- scanf("%d",&a[i][j]);
- int m=0,flag=1;
- k=0,h=0;
- if(n==1){
- printf("0 0");
- }
- else{
- for(i=0;i<n;i++){
- m=i;
- for(h=0;h<n;h++){
- if(a[i][k]<=a[i][h]){
- k=h;
- }
- }
- for(j=0;j<n;j++){
- if(a[m][k]>a[j][k]){
- m=j;
- break;
- }
- }
- if(i==m){
- flag=0;
- break;
- }
- }
- if(flag==0)
- printf("%d %d",i,k);
- else
- printf("NONE");
- }
- return 0;
- }
流程图:
来源: http://www.bubuko.com/infodetail-2995768.html
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