删除 MySQL 表中的数据
- MySQL> use sbtest;
- MySQL> select count(*) from sbtest1;
- +----------+
- | count(*) |
- +----------+
- | 1000 |
- +----------+
- 1 row in set (0.00 sec)
- MySQL> delete from sbtest1;
- Query OK, 1000 rows affected (0.21 sec)
- MySQL> select count(*) from sbtest1;
- +----------+
- | count(*) |
- +----------+
- | 0 |
- +----------+
- 1 row in set (0.00 sec)
确认时间点和当前二进制日志文件, 从二进制日志中读取操作记录
- mysqlbinlog \
- --start-datetime="2018-09-27 15:55:00" \
- --stop-datetime="2018-09-27 15:00:00" \
- --base64-output=decode-rows \
- --result-file=result.sql \
- -v /var/lib/MySQL/binlog.000022
其中的一条记录
去除不相关的内容
grep -A 5 "DELETE FROM \`sbtest\`.\`sbtest1\`" result.sql> 1.txt
提取数据
- grep "=" 1.txt> 2.txt
- sed -i 's/### //g' 2.txt
使用以下脚本生成 INSERT 语句
- [root@mysql03 tmp]# cat r2.sh
- #!/bin/bash
- vs=""
- while read line
- do
- n=`echo $line | awk -NF "=" '{print $1}'`
- v=`echo $line | awk -NF "=" '{print $2}'`
- if [ "$n" = "@1" ]; then
- vs="INSERT INTO \`sbtest\`.\`sbtest1\` VALUES("$v
- elif [ "$n" = "@2" ]; then
- vs=$vs","$v
- elif [ "$n" = "@3" ]; then
- vs=$vs","$v
- elif [ "$n" = "@4" ]; then
- vs=$vs","$v");"
- echo $vs>> 3.txt
- fi
- done <2.txt
- [root@mysql03 tmp]# sh r2.sh
将数据导入到 MySQL 表中
- [root@mysql03 tmp]# MySQL < 3.txt
- MySQL> select count(*) from sbtest1;
- +----------+
- | count(*) |
- +----------+
- | 1000 |
- +----------+
- 1 row in set (0.00 sec)
来源: http://www.linuxidc.com/Linux/2018-09/154488.htm