1, 从 List<Staff> 筛选符合条件的 List<String>:
- List<Staff> staffListtemp=Lists.newArrayList();
- List<String> staffIdList=staffListtemp.stream().filter(staff->deptIdSet.contains(staff.getDeptId())).map(staffId->staffId.getStaffId()).collect(Collectors.toList());
2, 从 List<PositionRealtime> 转为 Map<String,PositionRealtime>:
- List<PositionRealtime> prList
- Map<String,PositionRealtime> prMap=prList.stream().collect(Collectors.toMap(PositionRealtime::getStaffId, PositionRealtime->PositionRealtime));
3, 从 Set<String> 转为拼接后的 String:
- Set<String> inPostStaffIds = Sets.newHashSet();
- String inPostIds = inPostStaffIds.stream().reduce((a,b)->a+","+b).get();
4, 从 List<StaffGpsTimeDTO> 通过 StaffId 作为分组条件分组为 Map<String,List<StaffGpsTimeDTO>> 对象:
- List<StaffGpsTimeDTO> positionHistoryTimeList = positionHistoryManageDao.getPositionHistoryTimeList(filterPropertyMap2);
- for(StaffGpsTimeDTO staffGpsTimeDTO : positionHistoryTimeList){
- List<Date> list = Lists.newArrayList();
- if(gpsMap.get(staffGpsTimeDTO.getStaffId()) != null){
- list = gpsMap.get(staffGpsTimeDTO.getStaffId());
- }
- list.add(staffGpsTimeDTO.getGpsTime());
- gpsMap.put(staffGpsTimeDTO.getStaffId(), list);
- }
- Map<string,List<>> aaa=positionHistoryTimeList.stream().collect(Collectors.groupingBy(StaffGpsTimeDTO::getStaffId,Collectors.mapping(StaffGpsTimeDTO::getGpsTime, Collectors.toList())));
来源: http://www.bubuko.com/infodetail-2738613.html