A + B Problem II
- Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
- Total Submission(s): 399645 Accepted Submission(s): 77352
- Problem Description
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
- Output
- For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.
- Sample Input
- 2
- 1 2
- 112233445566778899 998877665544332211
- Sample Output
- Case 1:
- 1 + 2 = 3
- Case 2:
- 112233445566778899 + 998877665544332211 = 1111111111111111110
用 JAVA
- import java.math.BigInteger;
- import java.util.Scanner;
- public class Main {
- public static void main(String[] args) {
- Scanner in = new Scanner(System.in);
- int n;
- BigInteger a,b;
- n=in.nextInt();
- int i=0;
- while(n>0) {
- n--;
- a=in.nextBigInteger();
- b=in.nextBigInteger();
- i++;
- System.out.println("Case" + "" + i +":");
- if(n>0) {
- System.out.println(a + "+" + b + "="+a.add(b));
- System.out.println();
- }
- else {
- System.out.println(a + "+" + b + "="+a.add(b));
- }
- }
- }
- }
C++:
要审清题意, 注意输出格式!
- #include<string>
- #include <cstdio>
- #include<iostream>
- using namespace std;
- string add(string a,string b)
- {
- int len1=a.length();
- int len2=b.length();
- if(len1>len2)
- {
- for(int i=1;i<=len1-len2;i++)
- b="0"+b;
- }
- else
- {
- for(int i=1;i<=len2-len1;i++)
- a="0"+a;
- }
- int len=a.length();
- int cf=0,t;
- string str;
- for(int i=len-1;i>=0;i--)
- {
- t=a[i]-'0'+b[i]-'0'+cf;
- cf=t/10;
- t%=10;
- str=char(t+'0')+str;
- }
- if(cf!=0)
- str=char(cf+'0')+str;
- return str;
- }
- int main()
- {
- int t;
- cin>>t;
- int k=0;
- while(t--)
- {
- k++;
- string a,b;
- cin>>a>>b;
- string str;
- str=add(a,b);
- cout<<"Case"<<k<<":"<<endl;
- cout<<a<<"+"<<b<<"="<<str<<endl;
- if(t)
- cout<<endl;
- }
- return 0;
- }
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