已知:a = [(4,2,3), (5, 9, 1), (7,8,9)]
希望将二维列表转换成一维列表:["4,2,3", "5, 9, 1", "7,8,9"]
具体实现方法如下:
- >>> a = [(4,2,3), (5, 9, 1), (7,8,9)]
- >>> from itertools import chain
- >>> list(chain.from_iterable(a))
- [4, 2, 3, 5, 9, 1, 7, 8, 9]
- >>> from tkinter import _flatten # python2.7也可以from compiler.ast import flatten
- >>> _flatten(a)
- (4, 2, 3, 5, 9, 1, 7, 8, 9)
- >>> [‘,‘.join(map(str,t)) for t in a]
- [‘4,2,3‘, ‘5,9,1‘, ‘7,8,9‘]
- >>> from itertools import starmap
- >>> list(starmap(‘{},{},{}‘.format,a))
- [‘4,2,3‘, ‘5,9,1‘, ‘7,8,9‘]
- #笨办法,但是可以提供一种思路
- a = [(4, 2, 3), (5,9,1), (7,8,9)]
- i=0
- while i<3:
- a[i]=str(a[i])[1:3*3-1]
- i=i+1
- print (a[0:3])
- >>>
- [‘4, 2, 3‘, ‘5, 9, 1‘, ‘7, 8, 9‘]