技术 bsp src clas return subject std ges logs
- 一个整数n(1 <= n <= 20)
- n的阶乘
- 3
- 6
#include
#include
#include
using namespace std;
int main()
{
int n=0;
int sum=1;
cin>>n;
while(n>1)
{
sum*=n;
n-=1;
}
cout<
return 0;
}
2017.11.10
来源: http://www.bubuko.com/infodetail-2389989.html