- """
- 用python写一个程序,找出数组中差值为K的数共有几对
- 示例:
- 差值k=4 and 数组是[7, 6, 23,19,10,11, 9, 3, 15]
- 这样的结果是(7,11) (7,3) (6,10) (19,23) (15,19) (15,11) 共6对
- 从标准输入读入两行数据
- 5 2
- 1 5 3 4 2
- 第一行代表N和K, N是数组是一共有多少数字,K是所要求的差值
- 第二是数组,空白分格
- 输出到标准输出
- Sample Input #00:
- 5 2
- 1 5 3 4 2
- Sample Output #00:
- 3
- Sample Input #01:
- 10 1
- 363374326 364147530 61825163 1073065718 1281246024 1399469912 428047635 491595254 879792181 1069262793
- Sample Output #01:
- 0
- """
- def diff_of_element_list(lst, k):
- """黄哥python远程视频培训班
- https://github.com/pythonpeixun/article/blob/master/index.md
- 黄哥python培训试看视频播放地址
- https://github.com/pythonpeixun/article/blob/master/python_shiping.md
- """
- newlst = [i + k for i in lst]
- return len(set(lst) & set(newlst))
- if __name__ == '__main__':
- lst = [7, 6, 23,19,10,11, 9, 3, 15]
- k = 4
- print(diff_of_element_list(lst, k))
- lst = [1,5, 3, 4, 2]
- k = 2
- print(diff_of_element_list(lst, k))
- n, k = input("please input n and k:\\n").split()
- lst = input("plesae input {0} number:\\n".format(n)).split()
- lst = [int(i) for i in lst]
- print(diff_of_element_list(lst, int(k)))
- #该片段来自于http://www.codesnippet.cn/detail/2601201614482.html
来源: http://www.codesnippet.cn/detail/2601201614482.html