- #coding:utf-8
- """
- 设计一个"石头,剪子,布"游戏,有时又叫"Rochambeau",你小时候可能玩过,下面是规则.你和你的对手,在同一时间做出特定的手势,必须是下面一种手势:石头,剪子,布.胜利者从
- 下面的规则中产生,这个规则本身是个悖论.
- (a) 布包石头.
- (b)石头砸剪子,
- (c)剪子剪破布.在你的计算机版本中,用户输入她/他的选项,计算机找一个随机选项,然后由你
- 的程序来决定一个胜利者或者平手.注意:最好的算法是尽量少的使用 if 语句.
- 黄老师写于2013-4-8下午,在终端下运行python *.py
- 不同的平台可能会出现汉字编码问题。
- 在mac os 终端测试过。
- guess_list = ["石头","剪刀","布"]
- guize = [["布","石头"],["石头","剪刀"],["剪刀","布"]]
- computer = random.choice(guess_list)
- people = raw_input('请输入:石头,剪刀,布\\n').strip()
- if computer == people:
- print "平手,再玩一次!"
- elif [computer,people] in guize :
- print "电脑获胜!"
- else:
- print "人获胜!"
- 改写为英文版。
- """
- import random
- guess_list = ["stone","Scissors","Cloth"]
- guize = [["Cloth","stone"],["stone","Scissors"],["Scissors","Cloth"]]
- computer = random.choice(guess_list)
- people = raw_input('please input:stone,Scissors,cloth\\n').strip()
- if computer == people:
- print "No-win!"
- elif [computer,people] in guize :
- print "computer Victory!"
- else:
- print "People Victory!"
- #该片段来自于http://www.codesnippet.cn/detail/100920135777.html
来源: http://www.codesnippet.cn/detail/100920135777.html