- <?php
- $days = cal_days_in_month(CAL_GREGORIAN, 4, 2011);
- echo "返回2011-4的天数 ".$days."<br/>";
- $days = date('t', strtotime("2011-4-1"));
- echo "返回2011-4的天数 ".$days."<br/>";
- $days = date("t");
- echo "当前月的天数 ".$days."<br/>";
- ?>
- //该片段来自于http://www.codesnippet.cn/detail/110420132811.html
来源: http://www.codesnippet.cn/detail/110420132811.html