import col 独立 数据结构 如果 忽略 faye 个数
>>> alist=['Lydia','Miranda','Tony','Cody','Lorries']
>>> print(aList)
['Tom', 'Ruby', 'Eddie', 'Eric']
>>> alist[0]'Lydia'>>> alist[3]'Cody'>>> alist[-1]'Lorries'>>> alist[-4]'Miranda'
- aList = ['Lori', 'Martins', 'Marcus', 'Fayes', 'Anthony', 'Paul', 'Miranda', 'Ketty']print(aList[1:4]) # 自左向右,从0计数。取下标1至下标4之间的数字,包括1,不包括['Martins', 'Marcus', 'Fayes']print(aList[1:-1])# 取下标1到下标-1的值,不包括-1. -1是ketty['Martins', 'Marcus', 'Fayes', 'Anthony', 'Paul', 'Miranda']
- print(aList[0 : 3])['Lori', 'Martins', 'Marcus'] print(aList[: 3])#0可以忽略,
- 和上句效果一样 ['Lori', 'Martins', 'Marcus']
- print(aList[3:]) #如果想取到最后一个值,不能写-1,只能这么写['Fayes', 'Anthony', 'Paul', 'Miranda', 'Ketty']print(aList[3:-1])#这样下标-1的元素不会被包括['Fayes', 'Anthony', 'Paul', 'Miranda']切片操作的扩展 - 步长索引print(aList[::2])# 第三个索引值2被用作步长参数,代表每隔1个元素就取一下['Lori', 'Marcus', 'Anthony', 'Miranda']
- print(aList[::-1])# 效果等同"reverse"操作['Ketty', 'Miranda', 'Paul', 'Anthony', 'Fayes', 'Marcus', 'Martins', 'Lori']
- aList.append('追加')print(aList)['Lori', 'Martins', 'Marcus', 'Fayes', 'Anthony', 'Paul', 'Miranda', 'Ketty','追加']
- aList.insert(2,"插入") #不能批量insertprint(aList)['Lori', 'Martins','插入', 'Marcus', 'Fayes', 'Anthony', 'Paul', 'Miranda', 'Ketty', '追加']
- aList[1]="修改"#替换原来的Martinsprint(aList)['Lori','修改', '插入', 'Marcus', 'Fayes', 'Anthony', 'Paul', 'Miranda', 'Ketty', '追加']
方法 1 - list. remove("...")
- aList.remove("Lori")#删除方法1print(aList)['修改', '插入', 'Marcus', 'Fayes', 'Anthony', 'Paul', 'Miranda', 'Ketty', '追加'] 方法2 - del
- del aList[0]#删除方法2print(aList)['修改', '插入', 'Marcus', 'Fayes', 'Anthony', 'Paul', 'Miranda', 'Ketty', '追加']
- 方法3 - list.pop()
- aList.pop()#删除方法3,默认最后一位print(aList)['Lori', '修改', '插入', 'Marcus', 'Fayes', 'Anthony', 'Paul', 'Miranda', 'Ketty']
- bList = ['Wayne','Marcus']aList.extend(bList)print(aList)['Lori', 'Martins', 'Marcus', 'Fayes', 'Anthony', 'Paul', 'Miranda', 'Ketty', 'Wayne', 'Marcus']
- print(aList.index("Marcus")) #获取下标2print(aList[aList.index("Marcus")]) #对应获取下标的打印元素Marcus
- print(aList.count("Marcus"))2
- aList.sort()print(aList)['Anthony', 'Fayes', 'Ketty', 'Lori', 'Marcus', 'Marcus', 'Martins', 'Miranda', 'Paul', 'Wayne']
- aList.reverse() #翻转print(aList)['Wayne', 'Paul', 'Miranda', 'Martins', 'Marcus', 'Marcus', 'Lori', 'Ketty', 'Fayes', 'Anthony']
- aList1 = aList.copy() aList[2] = 'MARCUS WOO'aList[4][0] = 'alexander'print(aList)['Lori', 'Martins', 'MARCUS WOO', 'Fayes', ['alexander', 'pete'], 'Anthony', 'Paul', 'Miranda', 'Ketty'] print(aList1)#浅copy,
- 只copy第一层。这是由于list的存储方式导致的,alexander会改的原因是因为具有相同的内存地址。而第一层不是。 ['Lori', 'Martins', 'Marcus', 'Fayes', ['alexander', 'pete'], 'Anthony', 'Paul', 'Miranda', 'Ketty']
- import copyaList = ['Lori', 'Martins', 'Marcus', 'Fayes', ['alex','pete'],'Anthony', 'Paul', 'Miranda', 'Ketty']aList2 = copy.deepcopy(aList)#最终两个list完全独立aList[2]='MARCUS WOO'aList[4][0]='alexander'print(aList)['Lori', 'Martins', 'MARCUS WOO', 'Fayes', ['alexander', 'pete'], 'Anthony', 'Paul', 'Miranda', 'Ketty']print(aList2)['Lori', 'Martins', 'Marcus', 'Fayes', ['alex', 'pete'], 'Anthony', 'Paul', 'Miranda', 'Ketty']
- for i in aList:print(i)LoriMartinsMarcusFayesAnthonyPaulMirandaKetty
元祖是只读列表, 即一旦创建不可修改。 列表用 [], 而元组用()。针对元祖,只可以用 count 和 index
- aTuple = ('alex','jack')
Python 基础 - Day 2 Learning Note - 列表 & 元组
来源: http://www.bubuko.com/infodetail-2136856.html