a = {}b = ['1:a','2:b','3:c']map(lambda x:a.setdefault(x.split(':')[0], x.split(':')[1]), b)print a{'1': 'a', '3': 'c', '2': 'b'}#该片段来自于http://www.codesnippet.cn/detail/130220148705.html
来源: http://www.codesnippet.cn/detail/130220148705.html